DINDICATION OF CONTRADICTION OF SPECIAL RELATIVITY AND INTRODUCTION OF AN UNKNOWN PHYSICAL QUANTITY : A DEPTH VELOCITY VECTOR
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@To detect by an experiment the difference between the spaces in the rocket
a and b presented in the introduction, we consider a thought experiment
below.
@[Thought experiment 2]
@Let us consider the condition where the rocket a is at rest along the
axis on the heavenly body M in Fig.1a, and another rocket a in a is at rest.(see Fig.2)
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@In the center of the rockets a and a the light sources and are set, which share the axis with the light source , installed on the origin of the - axis on M. At the six points on M, in a and a, twelve clocks of the same kind are placed at equal distance }L/2 from the light sources, the clocks which work exactly at the same tempo when at rest: one clock is placed at each end on M, two clocks at each end in a and three clocks at each end in a. The clock placed at the point |L/2 on is expressed as which means ethe lock at the eft side of the light sourcef, while the one placed at the point =L/2 is expressed as meaning ethe lock at the ight side of the sourcef. In the same way, the four clocks in a are expressed as , , , . And the six clocks in a are expressed as , , , , , .
@Then we set three pairs of clocks ( and , and , and ) using the way of clock settings which was used by Einstein when he constructed special relativity.
@In this case, M is at rest relative to the center of the gravity and is regarded as ethe absolute rest framef. And the spreads of the lights , and emitted from the three sources which are at rest on M are thought to be
isotropic relative to the observer .
@Therefore, those six clocks can be said to agree with one another in
the absolute sense.
@The next clock setting is about and in the rocket a, which begins to move at the uniform velocity relative to M, and about and in the rocket a , which is still at rest in a.(see Fig.3)
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@Since these two pairs of clocks are set in the same way, we consider
the clock setting of and .
@Let us consider the case in which an observer , who is at rest on the heavenly body M, measures the time required for the light emitted from the source to reach . When measures the distance between and , which is L/2 in the rocket, it is @() because the rocket a contracts in the moving direction at the rate of . Therefore, by 's clock, the time required for to reach is@
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i‚Pj
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@On the other hand, the time required for to reach is
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i‚Qj
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@But, the clock ticks at the rate of : 1, compared with 's clock. Thus, from and , observes the time difference required for to reach and ,
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i‚Rj
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@That is, is sec. fast compared with .
@The same is true with the time difference between and . What we have to notice, however, is it is when measures the time that and disagree with each other. For the observer in the rocket a, these two clocks agree with each other. can not discuss the absolute time difference between them as it is.
@Then, as a next operation, a time adjustment is made so that and agree, which usually do not.
@In addition, the same adjustment is made about .(Of course we do not really have to make the clocks agree. Calculational
adjustment is enough)
@When observes this situation, , and agree with one another, while is sec. fast. Therefore, when the observer in the rocket a () compares with , the latter is sec. fast. This agrees with the prediction of special relativity.
@When the same clock setting and time adjustment are made about and in the rocket a the observer will find that is sec. fast comparing with.
@Next, we make a clock setting about and when the rocket a in the rocket a begins to move at the uniform velocity '. (see Fig.4)
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@Now, we regard the velocity of a observed by as , and when observes the time difference between and ,
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i‚Sj
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@as is clear from the previous consideration.
@[From the theory of relativity, ]
@ Then, as a next operation, a time adjustment is made in order to make agree with and .
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@In addition, the same adjustment is made about .
@When this situation is observed by , , , and agree with one another. But is sec. fast, and is sec. fast relative to these four clocks.
@Consequently, when the observer in the rocket a compares with , the former is
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i‚Tj
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@fast relative to the latter. This result contradicts the prediction of
special relativity.
@According to the supposition of ethe principle of relativityf, which
was used when special relativity was constructed, inertia1 frames moving
relatively are equal and so the laws of physics must be the same in every
inertial frame.@Thus, if the time difference between and in the rocket a (moving at the uniform velocity above the heavenly body M ) is sec., the time difference between and in the rocket a (moving at the uniform velocity in the rocket a) must be sec.
@But the thought experiment in this paper does not produce such an result.
@By the way, let us consider the clock settings of the four clocks in a rocket b which is in the rocket b in Fig.1b : , , and . (See Fig.5)
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Fig.5@In the rocket b(Fig.1b) the rocket bŒis at rest.
When the clock setting is made about and , they agree in the absolute sense.
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@The distance between , and , is L. The light source is at the center.
@ and are set when the rocket b is at rest in the rocket b. In this case, the light (emitted from the source in b) isotropically spreads a priori, and so we can say that and agree with each other in the absolute sense.
@Next, a clock setting about and in the rocket b moving at the uniform velocity in the rocket b.(see Fig.6)
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@When the observer in b () tells the time difference between these two clocks, is sec. fast relative to , as is clear from the previous consideration.
@So, to make agree with , a certain time adjustment " is made. And the same adjustment " is made about .
@When observes this situation, , and agree with one another, while is sec. fast relative to them.
@Consequently, as a matter of course, when the observer in the rocket b compares with , the latter is sec. fast relative to the former.
@This result agrees with the prediction of special relativity.
@As for the time difference Eq.( 5) between and , which is compared in the same way, however, the prediction does not agree
with that.
@The correspondence of clock settings between these four clocks (, , , ) and the clocks(, , , ) in the rocket a is as follows:
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Clocks in the rocket aŒ( Fig.4 )
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*@clocks whose times are set when the rocket aŒis moving at a uniform
velocity Œin the rocket a in motion.
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*@clocks whose times are set when the rocket aŒ is at rest in the rocket
a in motion.
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Clocks in the rocket bŒ( Fig.6 )
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*@clocks whose times are set when the rocket bŒis moving at a uniform velocity Œin the rocket b in motion.
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*@clocks whose times are set when the rocket bŒis at rest in the rocket
a in motion.
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@From eThought experiment 2f, we have presented the way to detect the
difference of physical state between the inside space of the rocket a (see
Fig.1a) and the rocket b. (see Fig.1b)
@Now, what makes the time difference between and disagree with the prediction of special relativity?
@To explain the cause, we only have to think the space in the rocket a
is moving at ea certain velocity f relative to some frame of reference.
@However. ethe absolute rest spacef does not exist in the real physical
space. So it is impossible to regard ea certain velocity' as a velocity
relative to such a frame of reference.
@Then, this paper supposes that the physical space has a double layer.
@That is, we suppose an imaginary rest space | a depth rest space | in the depth of the real physical space, and suppose that the space in the rocket a, in which the spread of light is thought anisotropic, is moving at the velocity relative to a depth rest space. In this case, we define that the space in the rocket a has a depth velocity vector . (see Appendix)
@On the other hand, the space in the rocket b, in which the spread of light is thought isotropic, does not have a depth velocity vector.
@However, a depth rest space is not a real space. It is an imaginary one
which is introduced in order to describe ethe extent of the space dragging
effect by mass' with an unknown physical quantity : a depth velocity vector.
If we suppose the light spreads isotropically relative to each point in
this rest space, we can understand the speed of light does not depend on
the velocity of the light source. As for a depth velocity vector, the physical
space itself does not have it. It is a vector whose start point is a depth
rest space and the end is the real physical space.
@Now, let us calculate the magnitude of a depth velocity vector introduced
in the consideration above.
@In this paper, the magnitude is calculated from the time difference between and ( sec.) predicted by special relativity, and Eq.( 5 ) predicted in this paper. Generally speaking, however., the direction of a vector is not clear. So the component of its direction of axis is regarded as (>0).
@In addition, we define as below :
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@From this, we obtain
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i‚Vj
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i‚Wj
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@The case we deal with is >0, so omit the minus solution,C
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i‚Xj
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@Now, we can get the component of a depth velocity vector in axis. If the same experiment is made about the direction of axis and axis, we can get the magnitude of , and .
@Therefore, we can get the magnitude of a depth velocity vector by synthesizing
the components of these three directions.
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